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Question

Physics Question on electrostatic potential and capacitance

A parallel plate capacitor with air between the plates has a capacitance of 10pF10\, pF. The capacitance, if the distance between the plates is reduced by half and the space between them is filled with a substance of dielectric constant 44 is

A

80pF80\, pF

B

96pF96 \,pF

C

100pF100 \,pF

D

120pF120 \, pF

Answer

80pF80\, pF

Explanation

Solution

Here, C1=ε0Ad=10PF(i)C_{1}=\frac{\varepsilon_{0}A}{d}=10\,PF \ldots\left(i\right) and C2=kε0Ad2=4×2ε0Ad(k=4)C_{2}=k\frac{\varepsilon_{0}A}{d 2}=\frac{4\times2\varepsilon_{0}A}{d} \left(\because k=4\right) =8×10(using(i))=8\times10 \left(using \left(i\right)\right) =80PF=80\,PF