Question
Physics Question on Electromagnetic waves
A parallel plate capacitor of capacitance 20μF is being charged by a voltage source whose potential is changing at the rate of 3V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively :
A
60μA, zero
B
zero, zero
C
zero, 60μA
D
60μA 60μA
Answer
60μA 60μA
Explanation
Solution
Capacitance of capacitor C=20μF
=20×10−6F
Rate of change of potential (dtdV)=3v/s
q=CV
dtdq=CdtdV
ic=20×10−6×3
=60×10−6A=60μA
As we know that id=ic=60μA