Question

A parallel-plate capacitor is connected to a cell. A sheet of dielectric and a metal sheet are now introduced between the plates of the capacitor, parallel to these plates. The electric intensity between the positive plate of the capacitor and the dielectric sheet is E₁, between the dielectric sheet and the metal sheet is E₂, and between the metal sheet and the negative plate is E₃. Then-

• A. E₁ = E₂ = E₃
• B. E₁ = E₂¹ E₃
• C. E₁¹ E₂ = E₃
• D. E₁ ¹ E₂¹ E₃

Answer 1

Answer: (A)

E₁ = E₂ = E₃

Answer 2

The dielectric sheet and the metal sheet are without charge. Apply Gauss law.