Question
Physics Question on electrostatic potential and capacitance
A parallel plate capacitor is charged and then isolated. The effect of increasing the plate separation on charge, potential and capacitance respectively are
A
constant, decreases, decreases
B
increases, decreases, decreases
C
constant, decreases, increases
D
constant, increases, decreases
Answer
constant, increases, decreases
Explanation
Solution
After separation charge is constant.
Capacity, C=dε0A
Capacitance decreases with increase in distance and V=CQ
Potential increases with decrease in capacitance (C).