Question

A parallel plate capacitor having charge Q on it and plate area A, has d separation between the plates. If one of the plates is pulled to make the final separation 2d, then work done in this process is-

• A. W = $\frac { \mathrm { Q } ^ { 2 } } { 2 \mathrm {~A} \epsilon _ { 0 } }$
• B. W =
• C. W =
• D. Cannot be calculated

Answer 1

Answer: (C)

W =

Answer 2

W = F.d = $\frac { \mathrm { Q } ^ { 2 } } { 2 \mathrm {~A} \epsilon _ { 0 } } \cdot \mathrm { d }$

=