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Question: A parallel plate capacitor has two square plates with equal and opposite charges. The surface charge...

A parallel plate capacitor has two square plates with equal and opposite charges. The surface charge densities on the plates are + σ\sigma and σ- \sigma respectively. In the region between the plates the magnitude of the electric field is.

A

σ2ε0\frac { \sigma } { 2 \varepsilon _ { 0 } }

B

σε0\frac { \sigma } { \varepsilon _ { 0 } }

C

0

D

None of these

Answer

σε0\frac { \sigma } { \varepsilon _ { 0 } }

Explanation

Solution

: The magnitude of the electric field between the plates is,

E=σ2ε0(σ2ε0)=σε0\mathrm { E } = \frac { \sigma } { 2 \varepsilon _ { 0 } } - \left( - \frac { \sigma } { 2 \varepsilon _ { 0 } } \right) = \frac { \sigma } { \varepsilon _ { 0 } }