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Question

Physics Question on electrostatic potential and capacitance

A parallel plate air capacitor is charged to a potential difference of V volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates

A

increases

B

decreases

C

does not change

D

becomes zero

Answer

increases

Explanation

Solution

According to question
QQ = constant and CC \downarrow therefore V V \uparrow