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Question

Physics Question on Wave optics

A parallel beam of light of wavelength 6000 ?6000\, ? gets diffracted by a single slit of width 0.3 mm0.3 \,mm. The angular position of the first minima of diffracted light is

A

2×10−32\times 10^{-3} rad

B

2.8×10−32.8\times 10^{-3} rad

C

1.8×10−31.8\times 10^{-3} rad

D

6×10−36\times 10^{-3} rad

Answer

2×10−32\times 10^{-3} rad

Explanation

Solution

Given, λ=6000 ?=6000×10−10m\lambda=6000\, ?=6000 \times 10^{-10} m and n=0.3mm=0.3×10−3mn=0.3 mm =0.3 \times 10^{-3} m 0.3×10−3×sin⁡θ=6000×10−100.3 \times 10^{-3} \times \sin \theta=6000 \times 10^{-10} sin⁡θ=2×10−3\sin \theta=2 \times 10^{-3} or θ=2×10−3 rad\theta=2 \times 10^{-3}\, rad