Question
Question: A parallel beam of light is incident from air at an angle \[\alpha \] on the side PQ of a right angl...
A parallel beam of light is incident from air at an angle α on the side PQ of a right angled triangular prism of a refractive index η=2. Light undergoes total internal reflection in the prism at the face PR when α has a minimum value of 45o. The angle θ of the prism is:
A. 15o
B. 22.5o
C. 30o
D. 45o
Solution
Hint – In questions we should remember the laws of refraction and specially the Snell’s law i.e.
n1sinα=n2sinβ, where α is angle of incidence and β is angle of refraction.
Formula used-
- n1sinα=n2sinβ
- Angle sum of a triangle is 180o
Complete step-by-step answer:
The ray will bend toward the normal since it goes from the rarer to denser medium and then strikes with the face PR and then TIR happens.
Given, η=2
αmin=45o
We know that, n1sinα=n2sinβ
1×sinα=n×sinβ
When the value of αmin=45oand η=2.
Then the value of sinβ=21
Therefore the value ofβ=30o
Here the new term δ is called the angle of deviation. It is defined as the difference of the angle between refraction and the incidence angle and this angle is made when there is a minimum two mediums of different refractive index as here it is air and glass.
δ=90−(180−(90+θ+β))
∴ Applying Snell's law at surface PR we get the equation as:
∴2sinδ=1 ∴sin(θ+β)=21 θ+β=45o θ+30o=45o Therefore,θ=15oHence, the correct option is A.
Note: In this question we should use Snell's law of refraction and basic geometry of triangles to find the angle as the sum of angles of a triangle is 180o. Doing this will solve your problem. Generally these types of problems arise from this chapter. So, learning the important formulas will be a better option for students.