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Question: A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at...

A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at 2 ms-2. He reaches the ground with a speed 3 ms-1. At which height did he bail out?

A

91 m

B

182 m

C

293 m

D

111 m

Answer

293 m

Explanation

Solution

v2 = 2gh = 2 × 10 × 50 d

= 50 + [322×10×502(2)]=293 m\left[ \frac { 3 ^ { 2 } - 2 \times 10 \times 50 } { - 2 ( 2 ) } \right] = 293 \mathrm {~m} s