Question
Physics Question on Gravitation
A parachutist, after bailing out, falls 50 m without friction. When parachute opens, it retards at 2 ms-2. He reaches the ground with a speed of 3 ms-1. At what height did he bail out?
A
(A) 293 m
B
(B) 111 m
C
(C) 91 m
D
(D) 182 m
Answer
(A) 293 m
Explanation
Solution
Explanation:
Let velocity at the end of 50m be u m/su2=2gh=2×9.8×50=980 units Let further displacement be s.s=v2−u22a−32−980−2×2s=980−94=9714=243∴ Total height =h+s=50+243=293m