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Question

Mathematics Question on Probability

A pair of unbiased dice is thrown once. Let XX be the random variable denoting the product of numbers that appear on the two dice. Then P(X21)=P\left(X \ge21\right)=

A

536\frac{5}{36}

B

736\frac{7}{36}

C

16\frac{1}{6}

D

112\frac{1}{12}

Answer

16\frac{1}{6}

Explanation

Solution

Let AA be the event such that the product of the numbers is greater than or equal to 2121.
A=(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)\therefore A = \\{(4,6), (5,5), (5,6), (6,4), (6,5), (6,6)\\}
Required probability =636 = \frac{6}{36}
=16= \frac{1}{6}