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Question: A pair of bullocks exerts a force of \[140N\] on a plough. The field being ploughed is \[15m\]long. ...

A pair of bullocks exerts a force of 140N140N on a plough. The field being ploughed is 15m15mlong. How much work is done in ploughing the length of the field?

Explanation

Solution

The most commonly used terms in Physics are work, energy, and power. They're most likely the first thing you learned in physics class. Work and energy can be thought of as two sides of a single coin. Work is usually measured in terms of the force applied, whereas energy is measured in terms of other factors such as heat. Power is defined as the amount of work completed in a given amount of time.

Complete step by step solution:
Force is defined as a push or a pull that can change the velocity and acceleration of any mass object. The magnitude and direction of force are both vector quantities. If the force acting on an object is zero, regardless of whether the object is in a dynamic or static state, the force does not work.
Displacement is a vector quantity that represents the shortest distance between an object's initial and final positions. The network done by a force acting on an object is zero if the resultant displacement in the direction of force is zero. For example, if we push a rigid wall with all our might and still can't get it to move, we can say "no work."
Depending on the direction of displacement of the object concerning the force, the work done by the force can be positive, negative, or zero. The work done by the force of friction on an object moving in the opposite direction to the direction of force, such as friction acting on an object moving forward, is negative.
Force is defined in physics as the push or pull on a mass object that causes it to change velocity.
When a force is applied to an object, work is said to be completed.
The joule (JJ) is the SI unit of work, and it is defined as the work done by a force of 1 Newton1\text{ }Newton moving an object a distance of 1 meter1\text{ }meterin the force's direction.
The expression gives work done by the bullocks:
Work done = Forced – Displacement
W= F  dW=\text{ }F\text{ }\text{ }d
Where,
Applied force, F = 140 NF\text{ }=\text{ }140\text{ }N
Displacement, d = 15 md\text{ }=\text{ }15\text{ }m
W= 140  15 = 2100 JW=\text{ }140\text{ }\text{ }15\text{ }=\text{ }2100\text{ }J
As a result, plowing the length of the field requires 2100 J of work.

Note:
When the angle of displacement is perpendicular to the force's direction, the object experiences zero force. Consider the case of a coolie who is lifting a mass on his head at a 90-degree angle to the force of gravity. Gravity does no work on the object in this situation.