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Question

Physics Question on Electromagnetic induction

A pair of adjacent coils has a mutual inductance of 2.5H2.5 \,H If the current in one coil changes from 00 to 40A40 \,A in 0.8s0.8\, s, then the change in flux linked with the other coil is

A

100Wb100\, Wb

B

120Wb120\, Wb

C

200Wb200\, Wb

D

250Wb250\, Wb

Answer

100Wb100\, Wb

Explanation

Solution

Given, M=2.5H,dIdt=4000.8=50As1M=2.5\,H, \frac{dI}{dt}=\frac{40-0}{0.8}=50As^{-1} Also, ε=MdIdt=dϕdt\varepsilon=M \frac{dI}{dt}=\frac{d\phi}{dt} or dϕ=MdI=2.5(400) d\phi=MdI=2.5\left(40-0\right) =100Wb=100\,Wb