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Question: A P-type semiconductor has acceptor levels 57 meV above the valence band. The maximum wavelength of ...

A P-type semiconductor has acceptor levels 57 meV above the valence band. The maximum wavelength of light required to create a hole is (Planck’s constant h = 6.6×10−346.6 \times 10^{- 34}J-s)

A

(a) 57 Å

A

(b) 57×10−3A˚57 \times 10^{- 3}Å

A

(c) 217100 Å

A

(d) 11.61×10−33A˚11.61 \times 10^{- 33}Å

Explanation

Solution

(c)

E=hcλE = \frac{hc}{\lambda} ⇒ λ=hcE=6.6×10−34×3×10857×10−3×1.6×10−19\lambda = \frac{hc}{E} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{57 \times 10^{- 3} \times 1.6 \times 10^{- 19}}= 217100 Å