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Question: A one mole of an ideal gas expands adiabatically at constant pressure such that its temperature T ![...

A one mole of an ideal gas expands adiabatically at constant pressure such that its temperature T The value of the adiabatic constant of gas is

A

1.3

B

1.5

C

1.67

D

2.0

Answer

1.5

Explanation

Solution

: In an adiabatic expansion.

PVγ=P V \gamma =constant

P=RTV\because P = \frac { R T } { V } (for 1 mole of gas)

(RTV)Vγ=\therefore \left( \frac { R T } { V } \right) V ^ { \gamma } =constant

As T1V1γ=12T \propto \frac { 1 } { \sqrt { V } } \therefore 1 - \gamma = - \frac { 1 } { 2 } γ=1+12=32=1.5\gamma = 1 + \frac { 1 } { 2 } = \frac { 3 } { 2 } = 1.5