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Question

Physics Question on electrostatic potential and capacitance

A number of condensers, each of the capacitance 1μF1 \, \mu F and each one of which gets punctured if a potential difference just exceeding 500V500 \,V is applied, are provided. An arrangement suitable for giving capacitance of 2μF2 \, \mu F across which 3000V3000 \,V may be applied requires at least

A

6 component capacitors

B

12 component capacitors

C

72 component capacitors

D

2 component capacitors

Answer

72 component capacitors

Explanation

Solution

Minimum number of condensers in each row =3000500=6=\frac{3000}{500}=6 If CC, is capacity of 66 condensers in a row, 1Cs=11+11+11+11+11+11=6\frac{1}{C_{s}}=\frac{1}{1}+\frac{1}{1} + \frac{1}{1} + \frac{1}{1} + \frac{1}{1} + \frac{1}{1} = 6 Cs=16μFC_{s}=\frac{1}{6} \mu F Let there be mm such rows in parallel, Total capacity =m×Cs=m \times C_{s} 2=m×162=m \times \frac{1}{6} m=12\therefore m=12 Total number of capacitors =6×12=6 \times 12 =72=72