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Question

Mathematics Question on Probability

A number is chosen at random from the set 1,2,3,,2000\\{1,2,3, \ldots , 2000\\} Let pp be the probability that the chosen number is a multiple of 33 or a multiple of 77. Then the value of 500p500\, p is_____

Answer

E = a number which is multiple of 3 or multiple of 7

n(E) = (3, 6, 9, …….., 1998) + (7, 14, 21, ……….., 1995) – (21, 42, 63, ……… 1995)

n(E) = 666+ 285 – 95

n(E) = 856

n(E) = 2000

P(E) = 8562000\frac{856}{2000}

P(E) × 500 = 8564\frac{856}{4} = 214