Question

A nuclide of an alkaline earth metal undergoes radioactive decay by emission of three $\alpha$-particles in succession. The group of the periodic table to which the resulting daughter element would belong is

• A. group 14
• B. group 16
• C. group 4
• D. group 6

Answer 1

Answer: (A)

group 14

Answer 2

After radioactive decay of element by three successive emission of $\alpha$-particles, the last element (stable) Pb is obtained which belongs to group 14 of periodic table.