Solveeit Logo

Question

Physics Question on Nuclear physics

A nucleus with mass number 240240 breaks into two a fragments each of mass number 120120, the binding energy per nucleon of unfragmented nuclei is 7.6MeV7.6\, MeV while that of fragments is 8.5MeV8.5\, MeV. The total gain in the Binding Energy in the process is :

A

0.9 MeV

B

9.4 MeV

C

804 MeV

D

216 MeV

Answer

216 MeV

Explanation

Solution

Final total binding energy
=2×8.5×120MeV=2040MeV=2 \times 8.5 \times 120 \,MeV =2040\, MeV
Initial total binding energy
=240×7.6MeV=1824MeV=240 \times 7.6\, MeV =1824\, MeV
Gain =(20401824)MeV=216MeV=(2040-1824) \,MeV =216\, MeV