Question

A nucleus ruptures into two nuclear parts which have their velocity ratio equal to 2 : 1. What will be the ratio of their nuclear sizes?

• A. 2^1/3 : 1
• B. 1: 2^1/3
• C. 3^1/2 : 1
• D. 1: 3^1/2

Answer 1

Answer: (B)

1: 2^1/3

Answer 2

m₁v₁ = m₁v₂ Ž = Ž $\frac { \frac { 4 } { 3 } \pi r _ { 1 } ^ { 3 } \mathrm {~d} } { \frac { 4 } { 3 } \pi r _ { 2 } ^ { 3 } \mathrm {~d} }$ =

Ž = $\frac { 1 } { 2 }$Ž = $\left( \frac { 1 } { 2 } \right) ^ { 1 / 3 }$