Question

A nucleus of mass number 189 splits into two nuclei having mass number 125 and 64. The ratio of radius of two daughter nuclei respectively is:

• A. 1:1
• B. 4:5
• C. 5:4
• D. 25:16:00

Answer 1

Answer: (C)

5:4

Answer 2

The correct answer is (c).
We know that
$R = R_0A(\frac{1}{3})$
$R_1 = R_0(125)(\frac{1}{3}) = 5R_0$
$R_2 = R_0(64)(\frac{1}{3}) = 4R_0$
$\frac{R_1}{R_2} = \frac{5}{4}$