Question

A nucleus disintegrates into two smaller parts, which have their velocities in the ratio $3: 2$ The ratio of their nuclear sizes will be $\left(\frac{x}{3}\right)^{\frac{1}{3}}$ The value of ' $x$ ' is:-

Answer 1

The correct answer is 2.

m1​v1​=m2​v2​⇒m2​m1​​=32​
Since, Nuclear mass density is constant
34​πr13​m1​​=34​πr23​m2​​
(r2​r1​​)3=m2​m1​​
r2​r1​​=(32​)31​
So, x=2