Question
Question: A nucleus \({}_{Z}^{A}X\) emits an α-particle. The resultant nucleus emits a \(\beta^{+}\)particle. ...
A nucleus ZAX emits an α-particle. The resultant nucleus emits a β+particle. The respective atomic and mass no. of the final nucleus will be.
A
Z – 3, A – 4
B
Z – 1, A – 4
C
Z – 2, A – 4
D
Z, A – 2
Answer
Z – 3, A – 4
Explanation
Solution
ZAX→Z−2A−4Y+24He→Z−3A−4Z+10B