Question

A nuclear transformation is denoted by $X\left(n, \alpha\right) \,^{7}_{3}Li.$ Which of the following is the nucleus of element $X$ ?

• A. $^{12}C_{6}$
• B. $^{10}_{5}B$
• C. $^{9}B_{5}$
• D. $^{11}Be_{4}$

Answer 1

Answer: (B)

$^{10}_{5}B$

Answer 2

$^{A}_{Z}X+^{1}_{0}n \rightarrow ^{7}_{3}Li+^{4}_{2}He$ It implies that $A + 1=7 + 4$ $\Rightarrow A=10$ and $Z + 0 = 3+2$ $\Rightarrow Z=5$ Thus, it is boron $^{10}_{5}B.$