Question

A nuclear reactor delivers a power of $10^9$ W. What is the amount of fuel consumed by the reactor in one hour ?

• A. 0.04 g
• B. 0.08 g
• C. 0.72 g
• D. 0.96 g

Answer 1

Answer: (A)

0.04 g

Answer 2

P = $\frac{E}{t} = \frac{mc^2}{t}$ $\therefore$ $m = \frac{Pt}{c^2} = \frac{10^9 \times 60 \times 60}{(3 \times 10^8)^2} = \frac{36 \times 10^{11}}{9 \times 10^{16}} = 4 \times 10^{-5}$ kg = 0.04 g