Question

A nuclear reaction of $^{235}_{92}U$ with a neutron produces $^{90}_{36}Kr$ and two neutrons. Other element produced in this reaction is

• A. $^{137}_{52}Te$
• B. $^{144}_{55}Cs$
• C. $^{137}_{56}Ba$
• D. $^{144}_{56}Ba$

Answer 1

Answer: (D)

$^{144}_{56}Ba$

Answer 2

$^{235}_{92}U + ^{1}_{0}n\to ^{144}_{56}Ba + ^{92}_{36}Kr + 2^{1}_{0} n$
Sum of atomic number of reactants = sum of atomic masses of products.