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Question: A nonconducting wire is bent as shown in the figure. Wire is given uniform charge density '$\lambda$...

A nonconducting wire is bent as shown in the figure. Wire is given uniform charge density 'λ\lambda'. Then electric field at origin 'O':

A

has magnitude zero

B

has magnitude (22)λ4πϵ0R\frac{(2-\sqrt{2})\lambda}{4\pi\epsilon_0 R}

C

is along the direction i^+j^2-\frac{\hat{i}+\hat{j}}{\sqrt{2}}

D

is along the direction i^+j^2\frac{\hat{i}+\hat{j}}{\sqrt{2}}

Answer

is along the direction i^+j^2\frac{\hat{i}+\hat{j}}{\sqrt{2}}

Explanation

Solution

I am unable to determine the correct explanation for this question.