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Question: A non-stoichiometric compound \[F{e_7}{S_8}\] consist of iron in both \[F{e^{2 + }}\]and \[F{e^{3 + ...

A non-stoichiometric compound Fe7S8F{e_7}{S_8} consist of iron in both Fe2+F{e^{2 + }}and Fe3+F{e^{3 + }} form and sulphur is present as sulphide ions. Calculate cation vacancies as a percentage of Fe2+F{e^{2 + }} initially present in the sample. (Express your answer as 100x%\dfrac{{100}}{x}\% and you should write x as answer)

Explanation

Solution

Calculate the total charge on both Fe and S. Afterwards calculate the ratio of Fe2+F{e^{2 + }} and Fe3+F{e^{3 + }} and use the formula to find the percentage.

Complete step by step answer:
Non-stoichiometric compounds are chemical compounds, almost always solid inorganic compounds, having elemental composition whose proportions cannot be represented by a ratio of small natural numbers.
A non-stoichiometric compound Fe7S8F{e_7}{S_8} consist of iron in both Fe2+F{e^{2 + }}and Fe3+F{e^{3 + }} form and sulphur is present as sulphide ions S2{S^{2 - }}.
Let the ratio of Fe2+F{e^{2 + }}and
Fe3+F{e^{3 + }} be x:y

Fe7S8 x+y=7  F{e_7}{S_8} \\\ x + y = 7 \\\

Balancing the charges of 8S28{S^{ - 2}}=16

Fe7+16 2x+3y=16  F{e_7}^{ + 16} \\\ 2x + 3y = 16 \\\

The values of x and y are:

x=5 y=2  x = 5 \\\ y = 2 \\\

So the given non-stoichiometric compound Fe7S8F{e_7}{S_8} ​ has 5, 2 and 8 number of Fe2+F{e^{2 + }}, Fe3+F{e^{3 + }} and S2{S^{2 - }} respectively .
To calculate the cation vacancies as a percentage of Fe2+F{e^{2 + }}:
Hence the formula is:

Cation vacancies = Fe2+×100total Fe =3×1008 =37.5%  Cation{\text{ vacancies = }}\dfrac{{F{e^{2 + }} \times 100}}{{total{\text{ }}Fe}} \\\ = \dfrac{{3 \times 100}}{8} \\\ = 37.5\% \\\

Additional information: A cation missing from its lattice site is called cation vacancies . To maintain electrical neutrality, one of the nearest metal ions acquires two positive charges. This type of defect occurs in compounds where metal can exhibit variable valency. e.g., Transition metal compounds like NiO, FeO, FeS etc.
Cations exhibit frenkel defects generally.
Frenkel defects are mostly exhibited in ionic solids where the smaller ion (usually the cation) is dislocated.

Note:
The question has asked the cation vacancies as a percentage of Fe2+F{e^{2 + }}. Kindly note to take Fe2+F{e^{2 + }}only in the formula of cation vacancies.