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Question: A non ideal solution was prepared by mixing 30 ml chloroform and 50 ml acetone. The volume of mixtur...

A non ideal solution was prepared by mixing 30 ml chloroform and 50 ml acetone. The volume of mixture will be.

A

> 80 ml

B

< 80 ml

C

= 80 ml

D

≥ 80 ml

Answer

< 80 ml

Explanation

Solution

Chloroform & acetone form a non-ideal solution, in which HH-bonding. Hence, the solution shows, negative deviation from Raoult’s Law i.e., ΔVmix=−ve\Delta V _ { m i x } = - v e ; ΔHmix=−ve\Delta H _ { m i x } = - v e

∴\therefore total volume of solution = less than (30 + 50 ml)

or <80ml< 80 \mathrm { ml }