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Question

Physics Question on electrostatic potential and capacitance

A non-conducting solid sphere of radius R is uniformly charged. The magnitude of the electric field due to the sphere at a distance r from its centre

A

increases as r increases for r < R

B

decreases as r increases for 0 < r < \infty

C

decreases as r increases for R < r < \infty

D

is discontinuous a r = R

Answer

decreases as r increases for R < r < \infty

Explanation

Solution

Inside the sphere E=14πε0.QR3rE=\frac{1}{4 \pi \varepsilon_0 }.\frac{Q}{R^3}r
\Rightarrow\hspace20mm E \propto r\, for\, r \le R
i.e. E at centre = 0 as r = 0 and E at surface =14πε0.QR2 =\frac{1}{4 \pi \varepsilon_0 }.\frac{Q}{R^2}
as \hspace25mm r = R
Outside the sphere
\hspace10mm E=\frac{1}{4 \pi \varepsilon_0 }.\frac{Q}{r^2} for rRr \ge R or E1r2E \propto \frac{1}{r^2}
Thus, variation of electric field (E) with distance (r) from the centre will be as shown.