Question

A newly discovered element $X$ is placed in the group $IA$ in the periodic table since it forms:
A.An oxide which is acidic.
B.A volatile chloride having a formula $XCl$
C.An ionic chloride having the formula $XCl$
D.An insoluble $XS{O_4}$

Answer 1

To solve this question, it is required to have knowledge of the periodic table. Any element of the group $IA$ in the periodic table is to have the properties of the alkali metals like sodium, lithium etc.

Complete step by step answer:
The alkali metals are the name given to the combined elements in group $IA$. These elements have only one electron in their valence shell and they get readily oxidized to form the monopositive ion to gain the octet configuration.
These elements form the oxide of the general formula ${X_2}O$ since their group valency is $\left( { + 1} \right)$ . These oxides dissolve in water to form hydroxides which are strongly basic in nature of the general formula $XOH$.
These elements form strong ionic compounds with the halide anions and they are readily soluble in water. With the sulphate ions also soluble salts are formed that are readily soluble in water.
Hence, the options A, B, and D regarding the placement of $X$ in group $IA$ are wrong.

So, the only correct option is C.

Note:
The alkali metals are called so due to the highly soluble nature of their bases in water forming alkalis. The alkali metals are lithium, sodium, potassium, rubidium, caesium, and francium, in their order in the group. The alkali metals are soft solids with low melting and boiling points and can be cut by a knife.