Question

A new alloy was found to break when a force of 90.8 N applied perpendicular to each end. The diameter of the wire is 1.84 mm. Find the breaking stress.

• A. 2.47 × 10⁷ Pa
• B. 1.43 × 10⁷Pa
• C. 3.41 × 10⁷ Pa
• D. 4.41 × 10⁷ Pa

Answer 1

Answer: (C)

3.41 × 10⁷ Pa

Answer 2

Breaking stress = $\frac{F}{A} = \frac{90.8 \times 10^{6}}{\pi \times (.92)^{2}}$ = 3.41 × 10⁷ Pa