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Question

Chemistry Question on Bohr’s Model for Hydrogen Atom

A near UVUV photon of 300nm300 \,nm is absorbed by a gas and then re-emitted as two photons. One photon is red with wavelength of the second photon is

A

1060 nm

B

496 nm

C

300 nm

D

215 nm

Answer

496 nm

Explanation

Solution

Energy values are additives. E=E1+E2E =E_{1}+E_{2} hcλ=hcλ1+hcλ2\frac{h c}{\lambda} =\frac{h c}{\lambda_{1}}+\frac{h c}{\lambda_{2}} or 1λ=1λ1+1λ2\frac{1}{\lambda}=\frac{1}{\lambda_{1}}+\frac{1}{\lambda_{2}} or 1300=1760+1λ2\frac{1}{300}=\frac{1}{760}+\frac{1}{\lambda_{2}} or 1λ2=13001760\frac{1}{\lambda_{2}}=\frac{1}{300}-\frac{1}{760} On solving λ=495.6nm\lambda =495.6 \,nm 496nm\approx 496 \,nm