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Question

Physics Question on Current electricity

A moving coil galvanometer of resistance 100Ω100 \Omega is used as an ammeter using a resistance 0.1Ω0.1 \Omega. The maximum deflection current in the galvanometer is 100μA100 \mu A. Find the current in the circuit, so that the ammeter shows maximum deflection.

A

100.0 mA

B

1000.0 mA

C

10.01 mA

D

1.01 mA

Answer

100.0 mA

Explanation

Solution

Vab=ig.G=(iig)Si=(1+GS)igV_{ab} = i_g.G = (i - i_g) S \, \, \, \, \, \, \Rightarrow \, \therefore \, i = \bigg( 1 + \frac{G}{S} \bigg) i_g
Substituting the values, we get
i=100.1mA\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, i = 100.1 mA
\therefore Correct answer is (a).