Question

A moving coil galvanometer has a resistance of $50\Omega$and gives full scale deflection for 10 mA. How could it be converted into an ammeter with a full scale deflection for 1A

• A. $50/99\Omega$ in series
• B. $50/99\Omega$ in parallel
• C. $0.01\Omega$ in series
• D. $0.01\Omega$ in parallel

Answer 1

Answer: (B)

$50/99\Omega$ in parallel

Answer 2

$S = \frac{i_{g} \times G}{i - i_{g}} = \frac{10 \times 10^{- 3} \times 50}{1 - 10^{- 3} \times 10} = \frac{50}{99}\Omega$ in parallel.