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Question

Physics Question on Moving charges and magnetism

A moving coil galvanometer has 150150 equal divisions. Its current sensitivity is 1010 divisions per milliampere and voltage sensitivity is 22 divisions per millivolt. In order that each division reads 1V1 V, the resistance in Ohm?s needed to be connected in series with the coil will be :

A

10310^3

B

10510^5

C

9999599995

D

99959995

Answer

99959995

Explanation

Solution

Full scale deflection current =15010mA=15mA=\frac{150}{10}mA=15\,mA Full scale deflection voltage =1502mV=72mV=\frac{150}{2} \,mV=72\,mV Galvanometer resistance G=75mV15mA=5ΩG=\frac{75mV}{15mA}=5\Omega Required full scale deflection voltage, V=1×150=150×VV = 1\times150 = 150\times V Let resistance to be connected in series is R.R. V=Ig(R+G)\Rightarrow V=I_{g}\left(R+G\right) 150=15×103(R+5)\therefore 150=15\times10^{-3}\left(R+5\right) 104=R+5\Rightarrow 10^{4}=R+5 R=100005=9995\Rightarrow R =10000-5 = 9995