Question
Question: A motorcycle moving with a speed of is subjected to an acceleration of \(5\;{\text{m}}{{\text{s}}^{ ...
A motorcycle moving with a speed of is subjected to an acceleration of 5ms−1Calculate the speed of the motorcycle after10seconds, and the distance travelled in this time.
Solution
Hint
The above problem can be solved by using the equation of the motions. There are three equations of motion. The speed, time acceleration and distance can easily be found by these three equations of motion.
Complete step by step answer
Given: The initial speed of the motorcycle is u=5ms−1, the time taken by the motorcycle is t=10s, the acceleration of the motorcycle is a=2ms−2.
Write the first equation of motion to find the final speed of the motorcycle.
⇒v=u+at......(1)
Substitute 5ms−1for u, 10seconds for t and ⇒2ms−2for a in the equation (1) to find the final speed of the motorcycle.
⇒v=5ms−1+(2ms−2)(10seconds)
⇒v=25ms−1
Write the third equation of motion to find the distance travelled by the motorcycle.
⇒v2=u2+2as
⇒s=2av2−u2......(2)
Substitute 5ms−1for u and 2ms−2for a in the equation (1) to find the distance travelled by the motorcycle.
⇒s=2(2ms−2)(25ms−1)2−(5ms−1)2
s=150m
Thus, the final speed of the motorcycle is 25ms−1 and the distance travelled by the motorcycle is 150m.
Additional Information
The speed of the particle is the same as the variation in the position of the particle with time and the acceleration is same as the consecutive variation in the position of the particle with time. The slope of the position- time graph describes the velocity and slope of the velocity-time graph describes the acceleration of the particle.
Note
The distance travelled by the motorcycle can also be found by using the second equation of motion and final speed of the motorcycle can be found by using the third equation of the motion.