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Question: A motor requires \(2\sec \) to go from a speed of\(60rpm\) to\(120rpm\) with a constant acceleration...

A motor requires 2sec2\sec to go from a speed of60rpm60rpm to120rpm120rpm with a constant acceleration. Number of revolutions it takes in this time is
A. 1.501.50
B. 4.54.5
C. 33
D. 6.06.0

Explanation

Solution

Hint:- Recall the concept of angular velocity. It is the velocity at which the particle rotates around a canter or a point in the given time. It is also known as rotational velocity. It shows how fast the position of an object changes with time.

Complete step-by-step solution :
Step I:
Given that time t=2sect = 2\sec
N1=60rpmN1 = 60rpm
1minute = 60seconds
60rpm=6060=1revolutionpersecond60rpm = \dfrac{{60}}{{60}} = 1 revolution per second
Similarly N2=120rpmN2 = 120rpm
120rpm=12060=2revolutionperseconds120rpm = \dfrac{{120}}{{60}} = 2 revolution per seconds
Step II:
Formula for angular velocity is written as ω=2nπ\omega = 2n\pi
Where ω\omega is the angular velocity
ω1=2n1π{\omega _1} = 2{n_1}\pi
ω1=2×1×π{\omega _1} = 2 \times 1 \times \pi
ω1=2πrad/sec{\omega _1} = 2\pi rad/\sec
Similarly, ω2=2×N2×π{\omega _2} = 2 \times N2 \times \pi
ω2=2×2×π{\omega _2} = 2 \times 2 \times \pi
ω2=4πrad/sec{\omega _2} = 4\pi rad/\sec
Step III:
Also the angular acceleration of the body is given by
=ω2ω1T\propto = \dfrac{{{\omega _2} - {\omega _1}}}{T}
=4π2π2\propto = \dfrac{{4\pi - 2\pi }}{2}
=2π2\propto = \dfrac{{2\pi }}{2}
=πrad/sec2\propto = \pi rad/{\sec ^2}
Step IV:
Angular displacement is the shortest angle between the initial and final positions for a given object having circular motion. It has both magnitude and direction. It is the angle of movement of a body in the circular path. So it is a vector quantity. It is known that if the angular acceleration, initial velocity and time are given, then angular displacement can be calculated using the formula
θ=ωt+12t2\theta = \omega t + \dfrac{1}{2} \propto {t^2}
Where θ\theta is angular displacement
ω\omega is the initial angular velocity
tt is the time taken
\propto is the angular acceleration
θ=2π×2+12π(2)2\theta = 2\pi \times 2 + \dfrac{1}{2}\pi {(2)^2}
θ=4π+2π\theta = 4\pi + 2\pi
θ=6π\theta = 6\pi
Step V:
To measure an angle, a radian is used. There are 2π2\pi radians in one complete revolution. Hence,
Number of revolutions is given by =6π2π=3 = \dfrac{{6\pi }}{{2\pi }} = 3.

Option C is the right answer.

Note:- It is to be noted that the terms angular acceleration and radial acceleration are different terms. Angular acceleration is the rate of change of angular velocity with time. An object with angular velocity will either rotate faster or slower. On the other hand, when an object undergoes circular motion then it shows radial acceleration.