Question

A motor pump lifts $6$ tonnes of water from a well of depth $25\, m$ to the first floor of height $35\, m$ from the ground floor in $20$ minutes. The power of the pump (in kW) is $[g = 10\, ms^{-2}]$

• A. 3
• B. 6
• C. 1.5
• D. 12

Answer 1

Answer: (A)

3

Answer 2

Given.
Height of first floor $(h)=35\, m$
Time $(t)=20 \,m$
We know that.
Power, $P=\frac{\text { work }}{\text { time }}$
$P =\frac{mgh}{t}$
$[\because \text { work }= mgh ]$
$=\frac{600 \times 10 \times(35-25)}{20}$
$=\frac{600 \times 10 \times 10}{20}$
$=\frac{6000}{2}=3000\, W =3 \,kW$