Question
Question: A motor car moving with a uniform speed of \(20 \mathrm {~m} / \mathrm { sec }\) comes to stop on ...
A motor car moving with a uniform speed of 20 m/sec comes to stop on the application of brakes after travelling a distance of 10 m Its acceleration is
A
20 m/sec2
B
−20m/sec2
C
−40m/sec2
D
+2m/sec2
Answer
−20m/sec2
Explanation
Solution
From v2=u2+2aS ⇒ 0=u2+2aS
⇒ a=2S−u2=2×10−(20)2=−20 m/s2