Question

A mosquito with 8 legs stands on water surface and each leg makes depression of radius 'a'. If the surface tension and angle of contact are 'T' and zero respectively then the weight of mosquito is-

• A. 8T.a
• B. 16 p Ta
• C. $\frac { \mathrm { Ta } } { 8 }$
• D. $\frac { \mathrm { Ta } } { 16 \pi }$

Answer 1

Answer: (B)

16 p Ta

Answer 2

Figure shows one of the legs of the mosquito landing upon the water surface. Therefore,

T.2pa × 8 = W = weight of the mosquito.