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Question

Physics Question on Thermodynamics

A monoatomic ideal gas, initially at temperature T1T_1, is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expand adiabatically to a temperature T2_2 by releasing the piston suddenly. If L1_1 and L2_2 are the lengths of the gas column before and after expansion respectively, then T1/T2T_1 / T_2 is given by

A

(L1/L2)2/3(L_1 /L_2)^{2/3}

B

(L1/L2)(L_1 /L_2)

C

L2/L1L_2/L_1

D

(L2/L1)2/3(L_2 /L_1)^{2/3}

Answer

(L2/L1)2/3(L_2 /L_1)^{2/3}

Explanation

Solution

During adiabatic expansion, we know
TVγ1=constantorT1V1γ1=T2V2γ1\, \, \, \, \, TV^{\gamma -1}=constant \, \, \, \, or \, \, T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}
For a monoatomic gas γ=53\gamma=\frac{5}{3}
T1T2=(V2V1)γ1=(AL2AL1)(5/3)1\therefore \, \, \, \, \, \, \, \frac{T_1}{T_2}=\bigg(\frac{V_2}{V_1}\bigg)^{\gamma-1} =\bigg(\frac{AL_2}{AL_1}\bigg)^{(5/3)-1}
\hspace20mm (A = Area of cross-section of piston)
\hspace20mm =(L2L1)2/3=\bigg(\frac{L_2}{L_1}\bigg)^{2/3}