Question

A monoatomic gas is compressed adiabatically to of its original volume, the final pressure of gas in terms of initial pressure P is

• A. 7.08 P
• B. 8.08 P
• C. 9.08 P
• D. 10.08 P

Answer 1

Answer: (D)

10.08 P

Answer 2

: the initial pressure and volume of gas are p and V.

Now the gas is compressed adiabatically to of its original volume, i.e.

As $P _ { 1 } V _ { 1 } ^ { \gamma } = P _ { 2 } V _ { 2 } ^ { \gamma }$…… (ii)

Or $P V ^ { \gamma } = p _ { 2 } \left( \frac { V } { 4 } \right) ^ { \gamma } = \frac { p _ { 2 } V ^ { \gamma } } { 4 ^ { \gamma } } ( u \sin g ( i ) )$

$P _ { 2 } = 4 ^ { \gamma } p$

Now for mono atomic gas

$\gamma = \frac { 5 } { 3 }$