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Question

Chemistry Question on Structure of atom

A monoatomic anion of unit charge contains 45 neutrons and 36 electrons. Identify the ion.

A

ClCl^-

B

FF^-

C

I{I^-}

D

BrBr^-

Answer

BrBr^-

Explanation

Solution

Let the monoatomic anion be XX^-.Number of electrons in X=36X- = 36
\therefore Number of electrons in monoatomic atom (X)(X)
=361=35= 36 - 1 = 35
Atomic number = number of electrons in neutral atom = number of protons in neutral atom =35 = 35
Mass number of monoatomic atom (X)(X) = number of protons + number of neutrons
=35+45=80= 35 + 45 = 80 Hence, ion must be BrBr^-.