Solveeit Logo

Question

Physics Question on Kinetic Energy

A monkey of mass mm kg slides down a light rope attached to a fixed spring balance, with an acceleration aa. The reading of the balance is wkg[g=w kg [g= acceleration due to gravity ]]

A

m=wggam=\frac{w g}{g-a}

B

m=w(1+ag)m=w\left(1+\frac{a}{g}\right)

C

the force of friction exerted by the rope on the monkey is m(ga)Nm(g-a)N

D

the tension in the rope is wgNwg\,N

Answer

the force of friction exerted by the rope on the monkey is m(ga)Nm(g-a)N

Explanation

Solution

The reading of the spring balance == tension in the rope == the force of friction between rope and the monkey =mgma=m(ga)N=m g-m a=m(g-a) N