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Question

Physics Question on laws of motion

A monkey of mass 40kg40 \,kg climbs ona massless rope which can stand a maximum tension of 500N500 \,N. In which of the following cases will the rope break? (Takeg=10ms2\, g=10\,m \,s^{-2})

A

The monkey climbs up with an acceleration of 5m5\,m s2s^{-2}

B

The monkey climbs down with an acceleration of 5m5\,m s2s^{-2}

C

The monkey climbs up with a uniform speed of 5m5\,m s1s^{-1}

D

The monkey falls down the rope freely under gravity

Answer

The monkey climbs up with an acceleration of 5m5\,m s2s^{-2}

Explanation

Solution

Here, mass of monkey, m=40kgm = 40\, kg Maximum tension the rope can stand, T=500NT = 500 \,N Tension in the rope will be equal to apparent weight of the monkey (R)(R). The rope will break when RR exceeds TT. (a) When the monkey climbs up with an acceleration a=5ma=5\,m s2s^{-2} R=mR=m (g+a)\left(g+a\right) =40(10+5)=40\left(10+5\right) =600N=600\, N \therefore R>TR >T Hence, the rope will break. (b) When the monkey climbs down with an acceleration a=5ma=5 \,m s2s^{-2} R=mR=m (ga)\left(g-a\right) =40(105)=40\left(10-5\right) =200N=200\, N \therefore\quad R<TR \,< \,T Hence, the rope will not break. (c) When the monkey climbs up with a uniform speed v=5mv=5\, m s1s^{-1}, its acceleration aa = 0 \therefore\quad R=mgR=mg =40×10=40\times10 =400N=400\, N \therefore\quad R<TR \,< T\, Hence, the rope will not break. (d) When the monkey falls down the rope freely under gravity a=ga=g \, \therefore\quad R=m(ga)=m(gg)R=m\left(g-a\right)=m\left(g-g\right)=zero Hence, the rope will not break.