Question
Physics Question on laws of motion
A monkey of mass 40kg climbs ona massless rope which can stand a maximum tension of 500N. In which of the following cases will the rope break? (Takeg=10ms−2)
The monkey climbs up with an acceleration of 5m s−2
The monkey climbs down with an acceleration of 5m s−2
The monkey climbs up with a uniform speed of 5m s−1
The monkey falls down the rope freely under gravity
The monkey climbs up with an acceleration of 5m s−2
Solution
Here, mass of monkey, m=40kg Maximum tension the rope can stand, T=500N Tension in the rope will be equal to apparent weight of the monkey (R). The rope will break when R exceeds T. (a) When the monkey climbs up with an acceleration a=5m s−2 R=m (g+a) =40(10+5) =600N ∴ R>T Hence, the rope will break. (b) When the monkey climbs down with an acceleration a=5m s−2 R=m (g−a) =40(10−5) =200N ∴ R<T Hence, the rope will not break. (c) When the monkey climbs up with a uniform speed v=5m s−1, its acceleration a = 0 ∴ R=mg =40×10 =400N ∴ R<T Hence, the rope will not break. (d) When the monkey falls down the rope freely under gravity a=g ∴ R=m(g−a)=m(g−g)=zero Hence, the rope will not break.