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Question: A monkey of mass 40 kg climbs on a massless rope which can stand a maximum tension of 500 N. In whic...

A monkey of mass 40 kg climbs on a massless rope which can stand a maximum tension of 500 N. In which of the following cases will the rope break?

(Take g=10 ms2\mathrm { g } = 10 \mathrm {~ms} ^ { - 2 } )

A

The monkey climbs up with an acceleration of 5 ms25 \mathrm {~ms} ^ { - 2 }

B

The monkey climbs down with an acceleration of 5 ms25 \mathrm {~ms} ^ { - 2 }

C

The monkey climbs up with a uniform speed of 5 ms25 \mathrm {~ms} ^ { - 2 }

D

The monkey falls down the rope freely under gravity

Answer

The monkey climbs up with an acceleration of 5 ms25 \mathrm {~ms} ^ { - 2 }

Explanation

Solution

Here mass of monkey m = 40kg

Maximum tension the rope can stand T = 500N

Tension in the rope will be equal to apparent weight of the monkey (R)

The rope will break when R exceeds T

(1) When the monkey climbs up with an acceleration a=5 ms2a = 5 \mathrm {~ms} ^ { - 2 }

R=m(g+a)=40(10+5)=600 NR = m ( g + a ) = 40 ( 10 + 5 ) = 600 \mathrm {~N}

R>T

Hence the roe will break

(2) When the monkey climbs down with an acceleration

a=5 ms2a = 5 \mathrm {~ms} ^ { - 2 }

R=m(ga)=40(105)=200 NR = m ( g - a ) = 40 ( 10 - 5 ) = 200 \mathrm {~N}

R<T

Hence the rope will not break

(3) When the monkey climbs up with a uniform speed

v=5ms1v = 5 m s ^ { - 1 } its acceleration a=0

R=mg=40×10=400 N\therefore R = m g = 40 \times 10 = 400 \mathrm {~N}

R<T

Hence the rope will not break

(4) When the monkey falls down the rope freely under gravity a=ga = g

R=mg(ga)=m(gg)=\therefore R = m g ( g - a ) = m ( g - g ) = zero

Hence the rope will not break