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Question: A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 kg is s...

A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope (g=10m/s2)\left( g = 10 m / s ^ { 2 } \right)

A

10 m/s210 \mathrm {~m} / \mathrm { s } ^ { 2 }

B

25 m/s225 \mathrm {~m} / \mathrm { s } ^ { 2 }

C

2.5m/s22.5 m / s ^ { 2 }

D

5m/s25 m / s ^ { 2 }

Answer

2.5m/s22.5 m / s ^ { 2 }

Explanation

Solution

Maximum tension that string can bear (Tmax) = 25 g N = 250 N

Tension in rope when the monkey climb up T=m(g+a)T = m ( g + a )

For limiting condition T=TmaxT = T _ { \max }m(g+a)=250m ( g + a ) = 250

20(10+a)=25020 ( 10 + a ) = 250

a=2.5 m/s2a = 2.5 \mathrm {~m} / \mathrm { s } ^ { 2 }