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Chemistry Question on Solutions

A molecule X associates in a given solvent as per the following equation:
X ⇌ (X)n
For a given concentration of X, the van’t Hoff factor was found to be 0.80 and the
fraction of associated molecules was 0.3. The correct value of ‘n’ is:

A

2

B

3

C

1

D

5

Answer

3

Explanation

Solution

The van’t Hoff factor i is related to the association factor n by the formula: i=1n Given that i=0.80, we can find the value of n as follows: n=10.80=1.25 Since the fraction of molecules associated is 0.3, the remaining fraction that is unassociated is 0.7. Therefore, n=3 is the correct value for the association factor.\text{The van’t Hoff factor } i \text{ is related to the association factor } n \text{ by the formula:} \\\ i = \frac{1}{n} \\\ \text{Given that } i = 0.80, \text{ we can find the value of } n \text{ as follows:} \\\ n = \frac{1}{0.80} = 1.25 \\\ \text{Since the fraction of molecules associated is } 0.3, \text{ the remaining fraction that is unassociated is } 0.7. \\\ \text{Therefore, } n = 3 \text{ is the correct value for the association factor.}